Question

How many moles of MgCl2 are there in 342 g of the compound?

Answer 1

3.6 moles of
`MgCl_2` are present in 342 g of
`MgCl_2`

Explanation:

Given the weight of compound
`MgCl_2` = 342 g

Atomic Mass of Mg = 24 amu

Atomic Mass of Cl = 35.5 amu

Computing the molar mass of
`MgCl_2` =
`(1 * 24)+(2 * 35.5)`amu = 24 + 71 = 95 amu

No. of moles of a compound is calculated by the formula =
`\frac{\text { Weight }}{\text { Molar Mass }}`

Substituting the value,

Moles =
`(342)/(95)=3.6 \mathrm{mol}`

Therefore, 3.6 moles of
`MgCl_2` are present in 342 g of
`MgCl_2`

Answer 2

There are 342 g/ 95. 2 g/m = 3.59 moles

Step-by-step explanation:

MgCl2 → Molar mass is 95.2g g/m

This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.

342 g/ 95. 2 g/m = 3.59 moles