Question

Write the equation of a line that is parallel to y=6x+1 and that passes through the point (-7 1)

Answer 1

Y = 6x + 43 is the line that passes through point (-7, 1).

Explanation:

Given line = Y = 6x + 1

From the slope intercept form y = mx + c; m= 6

For a parallel line, slopes must be equal i.e. m = 6

Now, for (-7, 1) and m = 6 we know that point slope form is
`\mathrm{Y}-\mathrm{Y}_(1)=\mathrm{m}\left(\mathrm{X}-\mathrm{X}_(1)\right)`

Line = Y – 1 = 6 (x-(-7))
`\Rightarrow` Y-1= 6(x+7)
`\Rightarrow` Y-1 = 6x+42
`\Rightarrow` Y = 6x + 43 Hence, the line is y = 6x + 43