Question

Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.

16x0 + 2x2 • y –1

Answer 1

Given that,

The given expression is :
`16x^0+2x^2{\cdot}y^(-1)`

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

`16x^0+2x^2{\cdot}y^(-1)`

Put x = 2 and y = 4 in the above expression.

`16x^0+2x^2{\cdot}y^(-1)\\\\=16* (2)^0+2(2)^2* (4)^(-1)\\\\=16* 1+2(2)^2*(1)/(4)\\\\=16+2\\\\=18`

So, the value of the above expression is 18.