Question

What is the surface-area-to-volume ratio of a cell whose six sides are 3 mm long

Answer 1

The required ratio is 2:1

Explanation:

Consider the provided information.

The surface area of a six sides cube, is 6s²

It is given that the sides are 3 mm long.

Therefore, the surface area is:

`6s^2=6(3)^2\\=6*9\\=54`

Hence, the surface area is 54 mm²

The volume of cube is
`s^3`

Therefore, the volume is:

`s^3=(3)^3\\=27`

We need to find the ratio of surface-area-to-volume

Therefore the required ratio is:

`\frac{\text{Surface area}}{Volume} =(54)/(27)=(2)/(1)`

Hence, the required ratio is 2:1