Question

Find the derivative of the function f(x) = 6x^-3 + x^2 + 14.

Answer 1

Explanation:

f(x) = 6x^-3 + x^2 + 14.

note : (x^n)' = n x ^(n-1)

f'(x) = (6)(-3) x^-4 +2x= -18 x^-4 +2x