Question

In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 500 nm. The diffraction patternis observed on a screen 10 m away. What is the spacing between successiveminima in the pattern.

Answer 1

`0.1` m

Step-by-step explanation:

`d` = slit width = 0.1 mm = 0.1 x 10⁻³ m

`\lambda` = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

`D` = Distance of the screen = 10 m

`w` = Spacing between successive minima

Spacing between successive minima is given as

`w = (2D\lambda )/(d)`

Inserting the values given

`w = (2(10)(500*10^(-9)) )/(0.1*10^(-3))`

`w = 0.1` m