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Given the equation square root of 2x-1=7 solve for x and identify if it is an extraneous solution. I came up with the answer 25 but is it an extraneous solution?

1 Answer

3 votes

Explanation:

To check if a solution is extraneous, simply plug it back into the original equation. If it works, then solution isn't extraneous.

√(2x−1) = 7

√(2(25)−1) = 7

√(50−1) = 7

√(49) = 7

7 = 7

So the solution isn't extraneous.

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User Jgreen
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