Question

What is the molarity of a 0.40 L Solution with 6.2 g KCl?

Answer 1

Molarity of KCl = 0.03M

Step-by-step explanation:

`Molarity=(W)/(GMW) * (1000)/(V(in\,ml))`

Given

Weight of
`$KCl$`
`=6.2g`

`V=0.40 L=400ml`

Gram Molecular weight
`=74.55g`

`Therefore Molarity = (6.2)/(74.55)*{1000}{400}\\                                =0.03M`