Question

Write an equation of the line passing through point P that is perpendicular to the given line P(6, -3), y

Answer 1

Equation of the line is:
`x=6`

Explanation:

We know that , the equation of any line parallel to y axis is :

`x=k` where
`k` ia a constant

And here it is given that the line is passing through the point P(6,-3)

Therefore, it will satisfy the equation
`x=k`.

So, substitute
`(6,-3)` in equation
`x=k`, we get

`k=6`

Hence the equation of line will be
`x=6`