A generator has a coil with 1260 turns that are each 0.090 m in diameter. The coil rotates at 3600 rpm in a 0.830 T magnetic field. If a 20.0 Ω resistive load is connected in pa…

Question

asked Jul 28, 2020 200k views

1 Answer

Wedava · Answer 1 · 2020-08-02T22:08:52+0000

Answer:

Step-by-step explanation:

Average power in AC is given as

$P = i_(rms) V_(rms) cos\phi$

As we know that when AC is connected across the Resistor then we will have

$cos\phi = 1$

now we have

P = (i_oV_o)/(2)

here we have

$V_o = NBA\omega$

$V_o = 1260(0.830)(\pi* 0.045^2)(2\pi (3600)/(60))$

V_o = 2508.15 Volts

now we have

P = (2508.15 * 2508.15)/(2 * 20)

P = 1.57 * 10^5 Watt