Question

If x =(20-4t^2) find average velocity between t=0and t=2sec​

Answer 1

The average velocity is 8 unit per sec

Step-by-step explanation:

Given as :

The Distance x = 20 - 4t² unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴ V =
`(\partial (20 - 4t^(2)))/(\partial x)`

Or, V = - 8t unit/s

Now velocity at t = 0

V1 = - 8 × 0 = 0 unit/s

And velocity at t = 2 sec

V2 = - 8 × 2 = - 16

So, Average velocity =
`(v2 - v1)/(2)` =
`(- 16 - 0)/(2)` = -8

Or,
`\begin{vmatrix}V\end{vmatrix}` = 8 unit/sec

Hence The average velocity is 8 unit per sec Answer