Question

A bag contains 5 milk and 13 dark chocolates.

A sweet is selected at random.
What is the probability of choosing:
P(milk)
=

P(not milk)
=

Answer 1

Answer:P(milk) 5/18 - 27% ----------- P(not milk) 13/18- 73%

Explanation:

total chocolates in the bag= 18 (5 milk chocolates + 13 dark chocolates= 18 chocolates in total)

to find percentages divide numerator by denominator ( 5/18 = 27%) (13/18=73%)

P(milk) - 27% chance you will get milk chocolate

P(not milk) 73% chance you will get dark chocolate

It is more likey to get dark chocolate