Question

Find the solutions to y = (x – 1)2 for x = –3, 0, and 3.

(–3, –16), (0, 1), (3, 4)

(–3, 16), (0, 1), (3, 4)

(–3, –2), (0, 1), (3, 4)

(–3, –4), (0, –1), (3, 2)

Answer 1

if the 2 is the power of (x-1) here is ur answer

`y = (x - 1 ){}^(2) \\if \: x \: is \: \: equal \: to \: - 3 \\ y =( - 3 - 1) {}^(2) \\ y = ( - 4) {}^(2) \\ y = 16`

`if \: x = 0 \\ y = (0 - 1) {}^(2) \\y = ( - 1) { }^(2) \\ y = 1`

`if \: x = 3 \\ y = (3 - 1) {}^(2) \\ y = 2 { }^(2) \\ y = 4`

(-3,16) (0,1) (3,4)