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If the product of two positive consecutive odd integers is 63, what’s the larger number ?

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User Janette
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1 Answer

3 votes

For this case we have:


x: Let the variable representing the first odd number


x + 2: Let the variable representing the consecutive odd number at x.

According to the statement we have:


x (x + 2) = 63\\x ^ 2 + 2x = 63\\x ^ 2 + 2x-63 = 0

We found the solution by factoring:

We look for two numbers that, when multiplied, result in -63 and when added, result in 2. These numbers are +9 and -7.


9-7 = 2\\9 * (-7) = -63

Thus, we have:


(x + 9) (x-7) = 0

Therefore the solutions are:


x_ {1} = - 9\\x_ {2} = 7

We choose the positive value, so we have:


x = 7\\x + 2 = 7 + 2 = 9

Answer:

The largest number is 9

answered
User Rajibdotnet
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8.1k points

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