Answer:
2.07
Step-by-step explanation:
Since you didn't supply the drawing, here is what I assumed: 
A is the corner opposite the axis of rotation 
B is one of the remaining two corners 
L1 is the side between A & B 
Centripetal acceleration is given by: 
 ac = v^2 / r = (v / r) * (v / r) * r…………1 
Also angular speed is 
w = v / r,………….2 
Substituting (2) in (1) gives: 
ac = (v / r) * (v / r) * r……….3 
= (v / r)^2 * r 
= w^2 * r 
Therefore, the angular acceleration at A and at B are given by: 
acA = w^2 * rA……..4 
acB = w^2 * rB……..5 
It is given that: 
acA = n * acB…………6 
Substituting (4) and (5) into (6) gives: 
w^2 * rA = n * w^2 * rB ……….7==> 
rA = n * rB……..8 
In terms of the sides L1 and L2: 
rA = sqrt (L1^2 + L2^2)…….9 
and 
rB = L2…………10 
Considering (8): 
n * L2 = sqrt (L1^2 + L2^2)………11 
Squaring both sides: 
n^2 * L2^2 = L1^2 + L2^2……….12 
Dividing by L2^2: 
n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13 
= (L1 / L2)^2 + 1 ==> 
n^2 - 1 = (L1 / L2)^2 ………14==> 
L1 / L2 = sqrt (n^2 - 1) ………15 
= sqrt (2.30^2 - 1) 
= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30