Question

A baseball of mass m = 0.16 kg is suspended vertically from a tree by a string of length L = 1.4 m and negligible mass. Take z as the upward vertical direction. A short-duration force F = Fyj + Fzk is applied to the baseball by a bat, momentarily creating a torque τ about the top of the string.Enter an expression for the torque due to the given force about the top of the string, in terms of m, L, Fy F , and the unit vectors i

Answer 1

`\tau = L F_y \hat i`

Step-by-step explanation:

As we know that torque due to applied force is given as

`\tau = \vec r * \vec F`

here we know that

`\vec r = -L\hat k`

applied force is given as

`\vec F = F_y \hat j + F_z \hat k`

now we will have

`\tau = (-L \hat k) * (F_y \hat j + F_z \hat k)`

`\tau = L F_y \hat i`