Question

Can I please get some help??

Answer 1

The answer to your question is: 3x
`\sqrt[5]{2x^(3)y^(3)  }`

Explanation:

=
`\sqrt[5]{486x^(8)y^(3)  }`

=
`\sqrt[5]{486} \sqrt[5]{x^(8) } \sqrt[5]{y^(3) }`

Find the prime factors of 486

486 2

243 3

81 3

27 3

9 3

3 3

1

Then, 486 = (2)(3⁵)

and x⁸ = x³x⁵

So

=
`\sqrt[5]{(2)(3^(5)) } \sqrt[5]{x^(3)x^(5)  } \sqrt[5]{y^(3) }`

= 3x
`\sqrt[5]{2x^(3)y^(3)  }`

= 3x(2x³y³)
`^(1/5)` or = 3x(2
`^(1/5) x^(3/5) y^(3/5)`