Question

Solve each quadratic equation using the most efficient method. 3x2+21x=0

Answer 1

For this case we have the following quadratic equation:

`3x ^ 2 + 21x = 0`

Dividing by 3 to both sides of the equation we have:

`x ^ 2 + 7x = 0`

We take common factor "x" from the left side of the equation:

`x (x + 7) = 0`

Thus, the values of "x" that satisfy equality are:

`x_ {1} = 0\\x_ {2} = - 7`

Answer:

The solutions are:

`x_ {1} = 0\\x_ {2} = - 7`