Question

Solve the system.
4x+y=2
x-y=3

Answer 1

do i solve by substitution or addition/elimination? my answer will be in the comments after you've replied

Explanation:

Answer 2

x = 1, y = -2 → (1, -2)

Explanation:

`\underline{+\left\{\begin{array}{ccc}4x+y=2\\x-y=3\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad5x=5\qquad\text{divide both sides by 5}\\.\qquad\boxed{x=1}\\\\\\\text{Put the value of}\ x\ \text{to the first equation:}\\\\4(1)+y=2\\4+y=2\qquad\text{subtract 4 from both sides}\\4-4+y=2-4\\\boxed{y=-2}`