Question

The number of atoms present in 2.5 mole of triatomic gas is equivalent to ​

Answer 1

Answer: 1.41725 X 10^{24} atoms

Step-by-step explanation:

One male of any gas containing no. of atoms
`$=6.023*10^(23)$`

2.5 moles of gas containing no. of atoms
`$=2.5*6.023*10^(23)$$=15.0575*10^(23)$`

The given gas is triatomic gas. Hence

No. of atoms
`$=3*15.075*10^(23)$`

`$=14.1725*10^(23)$\\$=1.41725*10^(24)$`