Question

What is the density(in g/L) of a gas with a molar mass of 32.49g/mol at 2.569atm and 458K?

Answer 1

2.22g/L

Step-by-step explanation:

Answer 2

`2.22~g/L`

Step-by-step explanation:

According to the ideal gas law equation:

`pV = nRT`

Let's express the number of moles in terms of mass and molar mass:

`pV = (m)/(M) RT`

Let's divide both sides by volume:

`p = (m)/(MV) RT`

Notice that:

`(m)/(V) = d`

So the equation becomes:

`p = (dRT)/(M)`

Expressing density:

`d = (pM)/(RT)`

Substituting the given values:

`d = (2.569~atm\cdot 32.49~g/mol)/(0.08206~(L~atm)/(mol~K)\cdot 458~K) = 2.22~g/L`