Question

F'(x)=2x-3. P(-3,3)​

Answer 1

y = x2- 3x +15

Explanation:

F'(x) = dy÷dx

=2x - 3

On integrating this function we get the function f (x)

y =( 2 x 2÷ 2) -3x +c

= x2 -3x + c

x -3 and y = 3

So 3 =( -3) × (-3) - 3 × (-3) + c

3 = 9 + 9 +c

3 = 18 + c

C = 15

Therefore the equation is

y = x2 - 3x +15