Answer:
Explanation:
The question is to find the equation of the line going through the points (3,-1) and has a slope of -1.
First, the equation of a line is given as:
Equation = y = mx + b
Where
m is the slope
b is the y-intercept (y-axis cutting point)
We know the slope, so the equation becomes:
y = mx + b
y = -1x + b
y = -x + b
Now the point given is in the form (x,y), so
x = 3
y = -1
We substitute and find b:
y = -x + b
-1 = -3 + b
-1 + 3 = b
b = 2
Final Equation:
y = -x + 2