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Question 2 If 4.500 mole letely, according to the following equation, what is the total change in enthalpy? 6CO2 + 6H,0—CH,206 +60, AHx = 2,803 kJ​

Question 2 If 4.500 mole letely, according to the following equation, what is the total change in enthalpy? 6CO2 + 6H,0—CH,206 +60, AHx = 2,803 kJ​
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Question 2

If 4.500 mole
letely, according to the following equation, what is the total change in enthalpy?
6CO2 + 6H,0—CH,206 +60,
AHx = 2,803 kJ​

asked
User Kishieel
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1 Answer

4 votes
Do this thing I haven’t learn it yet so wait till I learn it I’ll help u k
answered
User Marcogmonteiro
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