Question

Computer-controlled display screens provide drivers in the Indianapolis 500 with a variety of information about how their cars are performing. For instance, as a car is going through a turn, a speed of 93.8 m/s and centripetal acceleration of 4.13 g (4.13 times the acceleration due to gravity) are displayed. Determine the radius of the turn (in meters).

Answer 1

Answer:r=217.38 m/s

Step-by-step explanation:

Given

Speed of car
`v=93.8 m/s`

Centripetal acceleration
`a_c=4.13 g`

During a turn centripetal acceleration is given by
`(v^2)/(r)`

`a_c=(v^2)/(r)`

`r=(v^2)/(a_c)`

`r=(93.8^2)/(4.13g)`

`r=(93.8^2)/(4.13* 9.8)`

`r=(8798.44)/(40.474)`

`r=217.38 m`