Question

The experimental probability that tucker will win a game of chance is 2/5. The experimental probability that lily will win the same game is 5/8. If Tucker and Lily each play 200 games how many more games can lily expect to win that tucker

Answer 1

Lily can be expected to win 45 more games than Tucker.

Explanation:

The Probability of winning the game for Tucker = 2/5

The Probability of winning the game for Lily = 5/8

Total number of chances played = 200

Now,
`\textrm{Probability of winning an Event}  = \frac{\textrm{Total number of wins}}{\textrm{Total number of trials played}}`

⇒Total number of wins = P(winning ) x Number of Times it is played

Now, Total number of wins for Tucker =
`(2)/(5)  * 200 = 80`

or, Tucker wins 80 games out of 200 played.

And, Total number of wins for Lily =
`(5)/(8)  * 200 = 125`

or,Lily wins 125 games out of 200 played.

Hence, Lily is expected to win :

125 - 80 = 45 more games than Tucker.