asked 233k views
1 vote
A racquet ball with mass m = 0.223 kg is moving toward the wall at v = 14.7 m/s and at an angle of θ = 27° with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. While the ball is in contact with the wall, the average force the wall exerts on the ball has a magnitude of F = 94 N. 1)What is the magnitude of the initial momentum of the racquet ball?

asked
User Degr
by
9.2k points

1 Answer

0 votes

Answer:


P_i = 3.2781\ kg.m/s

Step-by-step explanation:

given,

mass of the ball = 0.223 Kg

velocity of the ball toward ball = 14.7 m/s

angle = θ = 27° w.r.t. horizontal

Average force exerted by the ball on the wall = 94 N

magnitude of initial momentum =


P_i = m_iv_i


P_i = 0.223* 14.7


P_i = 3.2781\ kg.m/s

so the initial momentum of the racket ball is
P_i = 3.2781\ kg.m/s

answered
User Sinar
by
8.4k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.