Question

The solution to the equation 2x^2+x-1=2

Answer 1

`x=-(3)/(2), x=1`

Explanation:

`2x^2+x-1=2`

Subtract 2 from both sides and factor:

`2x^2+x-1=2\\2x^2+x-3=0\\(2x+3)(x-1)=0`

Solve each factor individually:

`2x+3=0\\2x=-3\\x=-(3)/(2)`

`x-1=0\\x=1`