Register

A batter hits the a baseball so that it leaves the bat with an initial speed 37mps at an angle of 53degree find the position of ball after 2 second

A batter hits the a baseball so that it leaves the bat with an initial speed 37mps at an angle of 53degree find the position of ball after 2 second
asked 75.8k views
3 votes
A batter hits the a baseball so that it leaves the bat with an initial speed 37mps at an angle of 53degree find the position of ball after 2 second

asked
User EMgz
by
8.4k points

1 Answer

4 votes
Cos 53 degrees = adj/hyp
Cos 53 degrees = Vx/37mps
37 cos 53 degrees = Vx
Vx = 22.2 mps
sin 53 degrees = opp/hyp
sin 53 degrees = Vy/37 mps
37 mps sin 53 degrees = Vy
Vy = 29.54 mps
So, then
We are missing the altitude I believe
answered
User Leoluyi
by
7.2k points
← Prev Question Next Question →

Related questions

User Bdogru
asked Sep 1, 2022 125k views
In □PQRS side PQ∥ side RS. If m∠P = 108degree and m∠R = 53degree , then find m∠Q and m∠S.​
Bdogru asked Sep 1, 2022
by Bdogru
6.7k points
2 answers
0 votes
125k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
Link Copied!