Explanation:
Here given: AB II DE, AC = CE
Now, in ΔABC and ΔEDC
As, AB II DE (given)
⇒∠BAC = ∠CED (Alternative pairs of angles)
and ∠ABC = ∠CDE (Alternative pairs of angles)
and AC = CE (given)
So, by the congruent property of AAS
(ANGLE ANGLE SIDE) which states that two triangle are congruent if two angles and one side of one triangle is equal to the two angles and one side of the other triangle.
ΔABC ≅ ΔEDC