Question

A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, find the compression in the spring.

Answer 1

0.0316 m

Step-by-step explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

Elastic Potential stored = Kinetic energy of the block

`(1)/(2) kx^(2) = (1)/(2) mv^(2)`

x =
`\sqrt{v^(2)(m)/(k)  }`

x =
`\sqrt{1^(2)(1)/(1000)  }`

x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring