Question

A 6 μC point charge and a 9 μC point charge are initially infinitely far apart. How much work does it take to bring the 6 μC point charge to x = 3.0 mm, y = 0.0 mm and the 9 μC point charge to x = -3.0 mm, y = 0.0 mm? A 6 μC point charge and a 9 μC point charge are initially infinitely far apart. How much work does it take to bring the 6 μC point charge to x = 3.0 mm, y = 0.0 mm and the 9 μC point charge to x = -3.0 mm, y = 0.0 mm? 81 J 14 J 54 J 160 J

Answer 1

W = 80.91 J

Step-by-step explanation:

First we identify the variables we use for the calculation.

`W = (Kq_1 q_2)/(r)`

`q_1 = -6 x 10^(-6 )C`

`q_2 = - 9 x 10^(-6) C`

`r = 6 mm = 6 x 10^(-3) m`

`K = ( \pi \epsilon_0)/(4) = 8.99 x 109 N.m2/C2.`

In order to identify the missing variable, we proceed to calculate the work through the given formula. Substituting these values,

`W = \frac{(8.99 x 10^9) * (- 9 x 10^(-6)) * (- 6 x 10^(-6))} {(6 x 10^(-3))}`

`W = 80.91 J`