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The sum of three consecutive odd numbers in 177. What is the largest of the three numbers?

Step by step please!

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User Ducu
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2 Answers

2 votes

Answer:

91 is the largest of the three numbers.

Explanation:

Let the number be x, (x+2) and (x+4).

Given that the sum of these three odd consecutive numbers is 177.


x+(x+2)+(x+4)=177


3x+6=177


3x=177-6


3x=171


x=(171)/(3)=57

The number are : x = 57

(x+2) = 57 + 2 = 59

(x+4) = 57 +4 = 61

91 is the largest of the three numbers.

answered
User Jon Smock
by
7.5k points
2 votes

Answer:

1st odd = 57

2nd odd = 59

3rd odd = 61

Explanation:

Suppose the numbers to be:

1st odd = x -2

2nd odd = x

3rd odd = x +2

Now according to given conditions:

1st odd + 2nd odd + 3rd odd = 177

x - 2 + x +x + 2 = 177

By add -2 and + 2 will be cancelled

Adding all x

3x = 177

Dividing both sides by 3 we get

x = 177 / 3

x = 59

Now putting x = 59 to get three consecutive odds:

1st odd = x -2 = 59 - 2 = 57

2nd odd = x = 59

3rd odd = x +2 = 59 + 2 = 61

Proof:

1st odd + 2nd odd + 3rd odd = 177

57 + 59 + 61 = 177

177 = 177

hence proved

I hope it will help you!

answered
User Jimmy Huch
by
8.6k points

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