Answer:
x=110°
y=49°
Explanation:
Here consider ΔABD and ΔBCD as seperate.
In ΔABD
Given AB=AD which means that it is an isosceles triangle.
∠ABD=∠ADB
∠ADB=35°
In ΔABD sum of the angles =180°
∠BAD + 35° + 35° =180°
x=180°-70°=110°
In ΔBCD
Given BC=DC which means ΔBCD is an isosceles triangle.
∠CBD=∠CDB
∠CDB=y
∠CBD=y
In ΔBCD the sum of the angle =180°
y° + y° + 82°=180°
2y°=98°
y=49°