Question

F(x) = 8cos(2x) on (0,2π)

Answer 1

Explanation:

First put the lower limit, i.e., x=0,

F(x)=8cos[2(0)]=8cos(0)=8(1)=8

;cos(0)=1

Now,put the upper limit of given interval, i.e., x = π,

F(x)=8cos[2(π)]=8cos(2π)=8(1)=8

;cos(2π)=1