Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s1045 rad/s ). If a particular disk is spun at 264.9 rad/s264.9 rad/s while it is being read, and then is allowed to come to rest over 0.368 seconds0.368 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

719.84 rad/s²

Step-by-step explanation:

Given that:

`\omega_(initial)=264.9\ rad/s`

`\omega_(final)=0\ rad/s` (Has to come to rest)

t = 0.368 seconds

Thus, the expression for angular expression is:-

`\alpha=(\omega_(final)-\omega_(initial))/(t)`

Applying the values in the above equation as:-

`\alpha=(\omega_(final)-\omega_(initial))/(t)\\\Rightarrow \alpha=(0-264.9)/(0.368)\\\Rightarrow \alpha=-719.84\ rad/s^2`

Magnitude of the average angular acceleration = 719.84 rad/s²