Question

Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of hexane is mixed with 81.3 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Step-by-step explanation:

1. Write down the balanced chemical reaction:

`2C_(6)H_(14)_((l))+19O_(2)_((g))=12CO_(2)_((g))+14H_(2)O_((g))`

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

`70.0gC_(6)H_(14)*(1molC_(6)H_(14))/(86.2gC_(6)H_(14))=0.81molesC_(6)H_(14)`

For the oxygen:

`81.3gO_(2)*(1molO_(2))/(32.0gO_(2))=2.54molesO_(2)`

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

`(0.81)/(2)=0.41`

For the oxygen:

`(2.54)/(19)=0.13`

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

`81.3gO_(2)*(1molO_(2))/(32gO_(2))*(12molesCO_(2))/(19molesO_(2))*(44.0gCO_(2))/(1molCO_(2))=70.6gCO_(2)`