Question

HELP PLEASE

Consider the line y = 6x-7. Find the equation of the line that is perpendicular to this line and passes through the point (8, 3). Find the equation of the line that is parallel to this line and passes through the point (8, 3).​

Answer 1

y = (-x + 8)/6

Explanation:

y =6x-7

gradient of perpendicular to the line above is -1/6.

using the point (8,3)

y - y1 = m(x - x1)

y - 3 = -1/6(x - 8)

6y-18 = -1(x - 8)

y = (-x + 26)/6