Question

What are the period P and frequency T of oscillation of a pendulum of length one half​ft? (Hint: Upper P equals 2 pi StartRoot StartFraction Upper L Over 32 EndFraction EndRoot​,where L is the length of the pendulum in feet and the period P is in​ seconds.)

Answer 1

a

Explanation:

Answer 2

`P'=P \sqrt{(1)/(2)}`

T ' = √2 T

Explanation:

Given that

Time period = P

Frequency = T

We know that time period for pendulum given as

`P=2\pi \sqrt{(L)/(g)}`

When the length become half then time period will become p'

L'=L/2

`P'=2\pi \sqrt{(L')/(g)}`

`P'=2\pi \sqrt{(L)/(2g)}`

`P'=P \sqrt{(1)/(2)}`

It means that time period will become 0.707 P.

We know that frequency T

T= 1 /P

T' = 1/P'

T'=√2/P

T ' = √2 T