Write an equation in standard form that has a slip of 6 and passes through (-1,3)

Question

asked Jul 16, 2020 170k views

1 Answer

Art Spasky · Answer 1 · 2020-07-21T18:21:00+0000

Answer:

Explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have

$m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3$

Substitute:

y-3=6(x-(-1))

y-3=6(x+1)

Convert to the standard form Ax + By = C:

y-3=6(x+1) use the distributive property a(b + c) = ab + ac

y-3=6x+6 add 3 to both sides

y=6x+9 subtract 6x from both sides

-6x+y=9 change all signs

6x-y=-9