Question

A car starts from rest and accelerates for 8.9 s with an acceleration of 3.8 m/s 2 . How far does it travel? Answer in units of m.

Answer 1

150.5 m

Step-by-step explanation:

The motion of the car is a uniformly accelerated motion, so we can use the following suvat equation to find the displacement:

`s=ut+(1)/(2)at^2`

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

For the car in this problem,

u = 0

`a=3.8 m/s^2`

Substituting t = 8.9 s, we find the displacement of the car at that time:

`s=0+(1)/(2)(3.8)(8.9)^2=150.5 m`