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A sample of gas has a volume of 5.0 L and a pressure of 0.92 atm. If the final temperature is 303.15 K, the final volume is 5.7 L, and the final pressure is 1.05 atm, what was the initial temperature of the gas?

1 Answer

4 votes

Answer:

230 K

Explanation:

PV = nRT

If n is constant:

P₁ V₁ / T₁ = P₂ V₂ / T₂

(0.92 atm) (5.0 L) / T = (1.05 atm) (5.7 L) / (303.15 K)

T ≈ 230 K

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User David Ranieri
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