asked 33.0k views
1 vote
Jim is enclosing a rectangular garden with 170 feet of fencing. The length of the garden is 10 feet more than twice it's width, w. Determine the area of the garden.

asked
User Pnewhook
by
7.0k points

1 Answer

4 votes

Answer: Area = 1500 feet^2

Explanation:

Jim is enclosing a rectangular garden with 170 feet of fencing. This means the perimeter of the rectangular garden =170 feet

Let length = x

Let width = w

The length of the garden,x is 10 feet more than twice it's width, w. This means

x =10+2w---------1

Perimeter = 2x+2w =170---------2

Putting equation 1 in equation 2,

2(10+2w) +2w= 170

20 + 4w +2w = 170

6w = 170-20=150

w = 150/6

= 25feet

Put w=25 in equation 1

x =10 +2×25= 10+50=60 feet

Area = length × width = x×w

= 60×25=1500feet^2

answered
User Belema
by
8.4k points
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