The number of atoms of sulfur in 2.66 grams of sulfur

Question

asked Mar 20, 2020 102k views

1 Answer

Cathal Coffey · Answer 1 · 2020-03-26T05:04:47+0000

5.0 × 10^21 atoms of sulfur

We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's number.

Therefore;

1 mole of an element = 6.022 × 10^23 atoms

Thus, 1 mole of sulfur = 6.022 × 10^23 atoms

But, molar mass of sulfur = 32.065 g/mol

This means;

32.065 g contain 6.022 × 10^23 atoms

Therefore, 2.66 g of Sulfur will contain;

= (2.66 g ÷ 32.065 g/mol) × 6.022 × 10^23 atoms

= 5.0 × 10^21 atoms