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What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?

1 Answer

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Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Step-by-step explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

answered
User Dmitry Ginzburg
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