Is this set closed under multiplication D= {0} explain why or why not. Please help ASAP!!!

Question

asked May 5, 2020 183k views

1 Answer

Alina · Answer 1 · 2020-05-12T03:51:23+0000

Answer:

yes

Explanation:

The set is closed for a particular operation when that operation performed on members of the set results in a member of the set.

The product of 0 and 0 is 0, a member of the set, so the set is closed under multiplication.