Question

3. A rectangular coil of wire (a = 21.0 cm, b = 45.0 cm) containing a single turn is placed in a uniform 7.80 T magnetic field, as the drawing shows. The current in the loop is 18.0 A. Determine the magnitude of the magnetic force on the right side of the loop.

Answer 1

F = 29.484 N

Step-by-step explanation:

The force on the rod can containing the current placed in external magnetic field is:

F = BIL

where,

B = magnitude of the field

I = current in the loop

L = length

then,

F = 7.80 * 18.0 * 0.21

F = 29.484 N