Question

the Georgia aquarium in Atlanta is about 2.63*10^3 inches long, 1.26*10^2 inches wide, and 3*10^1 inches deep at it's largest point. Find it's approximate volume.​

Answer 1

`9.9414*10^(6)\ cubic\ inches\\`

Explanation:

Hello, I can help you with this ,

assuming the aquarium has a normal shape

The volume can be calculated with:

Volume= length*width*depth

Step one

according to the information in the question

`length\ =2.63*10^(3)\ inches \\width\ =1.26*10^(2)\ inches \\depth\ =3*10^(1)\ inches\\`

put the values into the equation

`Volumen=2.63*10^(3)\ inches *1.26*10^(2)\ inches *3*10^(1)\ inches`

combine similar terms

`Volumen=2.63*10^(3)\ inches *1.26*10^(2)\ inches *3*10^(1)\ inches\\Volume=(2.63*1.26*3)(10^(3)*10^(2)*10^(1))(inches *inches *inches )\\Volume=(9.9414)(10^(3+2+1))in^(3) \\Volume=(9.9414)(10^(6))in^(3)`

Have a good day.