Question

Can anyone help me thanks

Answer 1

C

Explanation:

We can use the vertex form of a quadratic equation, given by:

`f(x)=a(x-h)^2+k`

Where a is the leading coefficient and (h, k) is the vertex.

We are given that the vertex is (-3, 1).

Hence, h = -3 and k = 1. By substitution:

`f(x)=a(x-(-3))^2+(1)`

Simplify:

`f(x)=a(x+3)^2+1`

With this, we can eliminate B and D.

Notice that our parabola is curving downwards.

Therefore, our leading coefficient must be negative.

The only choice that leaves us with is C.

So, our function is:

`f(x)=-(x+3)^2+1`

And our final answer is C.