Question

20. Suppose that A is a number with log(A) = 1.352.
a. What is the value of log(1000A)?

Answer 1

Answer:4.352

Explanation:

Given

`\log \left ( A\right )=1.352`

we know

`\log \left ( x\right )=y`

Thus
`x=10^(y)`

Applying identity we get

`A=\left ( 10\right )^(1.352)`

`A=22.4905`

For
`\log \left ( 1000A\right )`

`=\log \left ( 1000* 22.49\right )`

`=\log \left ( 22490.5461\right )`

`=4.352`